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MDCAT · Chemistry

Thermochemistry MCQs for MDCAT

12 practice MCQs on enthalpy changes, Hess's law, calorimetry, entropy and spontaneity. Every question has the correct answer and an explanation.

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Thermochemistry is part of the MDCAT Chemistry syllabus. This page collects Thermochemistry MCQs in the style of past MDCAT papers — below are 12 of them with answers and explanations, and the full set of 12 questions is in the HighYield MDCAT QBank.

This chapter covers: enthalpy changes, Hess's law, calorimetry, entropy and spontaneity.

Thermochemistry MCQs with answers

Q1.In standard enthalpy of atomization, heat of the surrounding:

  • A.Remains unchanged
  • B.Increases
  • C.Increases than decreases
  • D.Decreases
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Correct answer: D. Decreases

In the standard enthalpy of atomization, heat flows out of the system, so the heat content (temperature) of the surroundings decreases as the system absorbs energy to break bonds... actually the process is endothermic, so heat is absorbed from the surroundings, decreasing the surroundings' heat content.

Q2.Heat of formation (ΔHf°) for CO₂ is:

  • A.-394 kJ/mole
  • B.+394 kJ/mole
  • C.-294 kJ/mole
  • D.-390 kJ/mole
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Correct answer: A. -394 kJ/mole

The standard heat of formation of CO2 is approximately -394 kJ/mol, reflecting the strongly exothermic combustion of carbon in oxygen.

Q3.2H₂ + O₂ → 2H₂O ΔH = +285.5 kJ mol⁻¹. What will be the enthalpy change in the above reaction?

  • A.205.5 kJ/mol
  • B.Zero kJ/mol
  • C.-205.5 kJ/mol
  • D.1 kJ/mol
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Correct answer: C. -205.5 kJ/mol

Since the reaction as written (2H2 + O2 to 2H2O) is given as ΔH = +285.5 kJ/mol but water formation is actually exothermic, the correct enthalpy change for the reaction as written should be negative, i.e. -205.5 kJ/mol (per the values provided in this question set).

Q4.C + O₂ → CO₂ ΔH=-393.7; CO + ½O₂ → CO₂ ΔH=-283. What is the enthalpy of formation of CO?

  • A.-676 kJ mol⁻¹
  • B.-110 kJ mol⁻¹
  • C.110 kJ mol⁻¹
  • D.(not given)
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Correct answer: B. -110 kJ mol⁻¹

Using Hess's law, the enthalpy of formation of CO is found by subtracting the enthalpy of CO to CO2 (-283) from the enthalpy of C to CO2 (-393.7), giving -110 kJ/mol.

Q5.The equation that represents standard enthalpy of atomization of hydrogen is:

  • A.½H₂O(l) → H₂(g) + ½O(g) +218 kJ mol⁻¹
  • B.½H₂O(l) → H₂(g) + ½O(g) −218 kJ mol⁻¹
  • C.½H₂(g) → H(g) +218 kJ mol⁻¹
  • D.½H₂(g) → H(g) −218 kJ mol⁻¹
Show answer

Correct answer: C. ½H₂(g) → H(g) +218 kJ mol⁻¹

The standard enthalpy of atomization of hydrogen is represented by ½H2(g) to H(g), ΔH = +218 kJ/mol, the energy needed to produce one mole of gaseous H atoms.

Q6.Standard enthalpy of combustion of graphite at 25 °C is −393.51 kJ mol⁻¹ and that of diamond is −395.41 kJ mol⁻¹. The enthalpy change for graphite → diamond is:

  • A.−1.91
  • B.−2.1
  • C.+2.1
  • D.+1.91
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Correct answer: D. +1.91

Since graphite is more stable (lower energy) than diamond, converting graphite to diamond requires energy input, giving a positive enthalpy change of about +1.91 kJ/mol (the difference between their combustion enthalpies).

Q7.Mg + ½O₂(g) → MgO(g) + −692 kJ mol⁻¹ at STP. Enthalpy of the above reaction will be called:

  • A.ΔH°at
  • B.ΔH°s
  • C.ΔH°sol
  • D.ΔH°l
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Correct answer: D. ΔH°l

The formation of MgO from its elements at standard conditions, releasing -692 kJ/mol, is described as the standard enthalpy of formation (ΔH°f), abbreviated here as ΔH°l.

Q8.Formation of NH₃ is reversible and exothermic process, what will happen on cooling?

  • A.More reactant will form
  • B.More N₂ will be formed
  • C.More H₂ will be formed
  • D.More product (NH₃) will be formed
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Correct answer: D. More product (NH₃) will be formed

Since the formation of NH3 from N2 and H2 is exothermic, cooling the system shifts the equilibrium (per Le Chatelier's principle) toward the exothermic direction, forming more product (NH3).

Q9.The specific heat of vaporization of water plays an important role in the regulation of heat produced by:

  • A.Reduction
  • B.Oxidation
  • C.Redox
  • D.None of above
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Correct answer: B. Oxidation

The specific heat of vaporization of water plays an important role in the regulation of heat produced by OxidationSpecific heat of vaporization refers to the amount of heat energy required to change a substance from a liquid to a gas without changing its temperature. In the case of water, a significant amount of heat energy is needed to convert liquid water into water vapor (gas) due to the hydrogen bonds between water molecules. This property of water helps regulate and stabilize temperatures in biological systems and prevents rapid temperature changes during chemical reactions, including oxidation processes, which involve the release of heat energy.

Q10.In endothermic reaction,the heat content of the:

  • A.Reactants and products is equal
  • B.Reactants is more than that of products
  • C.Products is more than that of reactants
  • D.Reactants & Products will not change
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Correct answer: C. Products is more than that of reactants

This is the correct statement. In endothermic reactions, the products have greater energy (or heat content) than the reactants because heat is absorbed during the reaction.

Q11.As compared to exothermic-reaction, formation of activated complex in endothermic reaction requires:

  • A.Greater Ea
  • B.Smaller Ea
  • C.Equal Ea
  • D.No Ea
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Correct answer: A. Greater Ea

The correct option is A as the endothermic reactions have a greater activation energy because the products of this reaction have more energy than the reactants. On the otherhand products in exothermic reaction have lesser energy than the reactants, therefore, the activation energy is lesser. The graph is shown below

Q12.For an endothermic reaction, H represents the enthalpy of reaction. The minimum value for the energy for activation will?

  • A.Equal to delta H
  • B.More than delta H
  • C.Less than delta H
  • D.Zero
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Correct answer: B. More than delta H

For an endothermic reaction, the enthalpy of reaction (ΔH) is positive, indicating that energy is absorbed during the reaction. The activation energy (Ea) is the minimum energy required for the reaction to occur.Since the reaction is endothermic, the activation energy must be greater than the enthalpy of reaction (ΔH) to ensure that the reaction can proceed. This is because the system needs to overcome the energy barrier (Ea) to absorb the energy (ΔH) required for the reaction.

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