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MDCAT · Chemistry

Electrochemistry MCQs for MDCAT

23 practice MCQs on oxidation numbers, redox reactions, electrochemical cells, electrolysis and electrode potentials. Every question has the correct answer and an explanation.

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Electrochemistry is part of the MDCAT Chemistry syllabus. This page collects Electrochemistry MCQs in the style of past MDCAT papers — below are 12 of them with answers and explanations, and the full set of 23 questions is in the HighYield MDCAT QBank.

This chapter covers: oxidation numbers, redox reactions, electrochemical cells, electrolysis and electrode potentials.

Electrochemistry MCQs with answers

Q1.The nature of cathode rays in discharge tube:

  • A.Depends on the nature of gas taken in the discharge tube
  • B.Depends upon the nature of cathode in discharge tube
  • C.Is independent of the nature of the gas in discharge tube
  • D.Depends upon the nature of anode in the discharge tube
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Correct answer: C. Is independent of the nature of the gas in discharge tube

Cathode rays consist of electrons and are independent of the nature of the gas used in the discharge tube, since electrons are a universal constituent of all matter.

Q2.In electrolytic cell, a salt bridge is used in order to:

  • A.Pass the electric current
  • B.Prevent the flow of ions
  • C.Mix solution of two half cells
  • D.Allow movement of ions between two half cells
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Correct answer: D. Allow movement of ions between two half cells

A salt bridge in an electrolytic (or galvanic) cell allows the movement of ions between the two half-cells, completing the circuit and maintaining electrical neutrality.

Q3.In MgCl₂, the oxidation state of 'Cl' is

  • A.Zero
  • B.+2
  • C.-2
  • D.-1
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Correct answer: D. -1

In MgCl2, chlorine exists as the chloride ion with an oxidation state of -1, balancing magnesium's +2 charge.

Q4.In SO₄²⁻ the oxidation number of Sulphur is

  • A.-8
  • B.+8
  • C.-6
  • D.+6
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Correct answer: D. +6

In SO4^2-, with oxygen at -2 each (total -8) and an overall charge of -2, sulfur must have an oxidation number of +6 to balance the equation.

Q5.Oxidation state of 'Mn' in KMnO₄, K₂MnO₄, MnO₂ and MnSO₄ is in the order:

  • A.+7, +6, +2, +4
  • B.+6, +7, +2, +4
  • C.+7, +6, +4, +2
  • D.+4, +6, +7, +2
Show answer

Correct answer: C. +7, +6, +4, +2

The oxidation states of manganese are +7 in KMnO4, +6 in K2MnO4, +4 in MnO2, and +2 in MnSO4.

Q6.Oxidation state of 'Fe' in K₃[Fe(CN)₆] is:

  • A.+2
  • B.+3
  • C.-6
  • D.-3
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Correct answer: B. +3

In K3[Fe(CN)6], with K contributing +3 total and each CN- ligand contributing -1 (6 × -1 = -6), iron must have an oxidation state of +3 to balance the overall neutral charge.

Q7.An electrochemical cell is based upon which reaction?

  • A.Acid-base reaction
  • B.Redox reaction
  • C.Nuclear reaction
  • D.Neutralization reaction
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Correct answer: B. Redox reaction

An electrochemical cell is based on a redox reaction. Redox reactions involve the transfer of electrons between species. In an electrochemical cell, this transfer of electrons is facilitated through the separation of the oxidation and reduction half-reactions, which occur at different electrodes.

Q8.Which of the following transition metals show a 3d5 configuration in their +2 oxidation state?

  • A.Cu+2
  • B.Fe+2
  • C.Mn+2
  • D.Zn+2
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Correct answer: C. Mn+2

Mn²⁺: Manganese in the +2 oxidation state has an electron configuration of [Ar] 3d⁵, which is a half-filled d-subshell, making it stable.

Q9.Which step is irrelevant concerning the balancing of redox equations by the oxidation number method?

  • A.Split the reaction into two half reactions.
  • B.Assign an oxidation number to all the atoms involved in the equation.
  • C.Identify the element changing oxidation number
  • D.Equalize the number of electrons lost and gained
Show answer

Correct answer: A. Split the reaction into two half reactions.

Option A is correct. That step belongs to the ion–electron (half-reaction) method, not the oxidation number method.In the oxidation number method, you:Assign oxidation numbers.Identify atoms changing oxidation state.Equalize the total increase and decrease in oxidation number.Balance the remaining atoms and charges.So, splitting into half-reactions is not required here.

Q10.The oxidation number of 'Mn' in KMnO4, is

  • A.0
  • B.+1
  • C.-7
  • D.+7
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Correct answer: D. +7

In KMnO₄, Mn has an oxidation number of +7. This is determined by balancing the oxidation states of the other elements (K and O) in the compound, and it is one of the highest oxidation states Mn can achieve in compounds.

Q11.The oxidation number of cobalt in the given coordination complex is:[Co(H2NCH2CH2NH2)3]2(SO4)3

  • A.III
  • B.II
  • C.IV
  • D.VI
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Correct answer: A. III

In the given complex, [Co(H2NCH2CH2NH2)3]2(SO4)3 Cobalt is bonded with three molecules of ethylenediamine which is a bidendate ligand having neutral charge. Moreover the coordination sphere is bonded with three molecules of sulphate ions each having -2 charge. Using formula: Charge of Metal + Charge on Ligand + Charge on coordination sphere 2(x + 3(0) ) = 3(-2) 2x = -6 x = -3

Q12.Which of the following cell reactions correctly represent the electrolysis of water?

  • A.2H+ + 2e –->H2(g)
  • B.2H2O +2e —> H2(g)+2(OH-)
  • C.2(OH-) —> 2H2O + O2(g) +4e
  • D.2H2O —> O2(g) +4H+ + 4e
Show answer

Correct answer: D. 2H2O —> O2(g) +4H+ + 4e

Here's a breakdown of the electrolysis of water:Cathode: Water is reduced to hydrogen gas. 2H+ + 2e- -> H2(g) Anode: Water is oxidized to oxygen gas. 2H2O -> O2(g) + 4H+ + 4e- The overall reaction is the sum of these two half-reactions:2H2O -> 2H2(g) + O2(g)Therefore, the correct answer is d, which represents the overall reaction at the anode.

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